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प्रश्न
Solve the following equation by trial and error method:
3m - 14 = 4
उत्तर
Let m = 1
Therefore, 3m − 14
= 3 × 1 − 14
= 3 − 14
= −11
But, −11 ≠ 4
L.H.S. ≠ R.H.S.
Now, let's assume m = 2
Therefore, 3m − 14
= 3 × 2 − 14
= 6 − 14
= −8
But, −8 ≠ 4
L.H.S. ≠ R.H.S.
Now, let's assume m = 3
Therefore, 3m − 14
= 3 × 3 − 14
= 9 − 14
= −5
But, −5 ≠ 4
L.H.S. ≠ R.H.S.
Now, let's assume m = 4
= 12 − 14
= −2
But, −2 ≠ 4
L.H.S. ≠ R.H.S.
Now, let's assume m = 5
Therefore, 3m − 14
= 3 × 5 − 14
= 15 − 14
= 1
But, 1≠ 4
L.H.S. ≠ R.H.S.
Now, let's assume m = 6
Therefore, 3m − 14
= 3 × 6 − 14
= 18 − 14
= 4
Therefore, m = 6
L.H.S. = R.H.S.
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संबंधित प्रश्न
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| Equation | Value | Say, whether the Equation is Satisfied. (Yes/No) |
| `m/3 = 2` | m = -6 |
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Solve the following equation and verify the answer:
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5(x-1) +2(x+3) + 6 = 0
State which of the following are equations (with a variable). Give reason for your answer. Identify the variable from the equations with a variable.
x − 2 = 0
Complete the entries in the third column of the table.
|
S.No. |
Equation |
Value of variable |
Equation satisfied Yes/No |
|
(a) |
10y = 80 |
y = 10 |
______ |
|
(b) |
10y = 80 |
y = 8 |
______ |
|
(c) |
10y = 80 |
y = 5 |
______ |
|
(d) |
4l = 20 |
l = 20 |
______ |
|
(e) |
4l = 20 |
l = 80 |
______ |
|
(f) |
4l = 20 |
l = 5 |
______ |
|
(g) |
b + 5 = 9 |
b = 5 |
______ |
|
(h) |
b + 5 = 9 |
b = 9 |
______ |
|
(i) |
b + 5 = 9 |
b = 4 |
______ |
|
(j) |
h − 8 = 5 |
h = 13 |
______ |
|
(k) |
h − 8 = 5 |
h = 8 |
______ |
|
(l) |
h − 8 = 5 |
h = 0 |
______ |
|
(m) |
p + 3 = 1 |
p = 3 |
______ |
|
(n) |
p + 3 = 1 |
p = 1 |
______ |
|
(o) |
p + 3 = 1 |
p = 0 |
______ |
|
(p) |
p + 3 = 1 |
p = − 1 |
______ |
|
(q) |
p + 3 = 1 |
p = − 2 |
______ |
