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Solve the following equations12x3 + 8x = 29x2 – 4 = 0 - Mathematics

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प्रश्न

Solve the following equations
12x3 + 8x = 29x2 – 4 = 0

बेरीज

उत्तर

12x3 + 8x = 29x2 – 4

12x3 – 29x2 + 8x + 4 = 0  ......(1)

By Trail and error method, (x – 2) is a factor of (1)

The other factor is 12x2 – 5x – 2

The roots is 12x2 – 5x – 2 = 0

(3x – 2)(4x + 1) = 0

x = `2/3`, x = `- 1/4`

The roots are `2, 2/3, - 1/4`

Here an = 12, a0 = 4

Let `"p"/"q"` be the root of the equation (1)

The factors of a0: ±1, ±2, ±4 .....(P must divisible by 4)

The factor of an: ±1, ±2, ±3, ±4, ±6, ±12

q must divide as (12)

Using these p and q we can form

`+-  1, +-  2, +- 1/2, +- 2/3, +- 1/6, +- 1/4, +- 3/4, +- 3` are the possible roots of equation (1)

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Theory of Equations - Exercise 3.5 [पृष्ठ १२४]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 3 Theory of Equations
Exercise 3.5 | Q 1. (ii) | पृष्ठ १२४
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