Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation by factorisation:
2x2 + ax - a2 = 0 where a ∈ R.
उत्तर
2x2 + ax - a2 = 0
⇒ 2x2 + 2ax - ax - a2 = 0
⇒ 2x(x + a) -a(x + a) = 0
⇒ (x = a) (2x - a) = 0
⇒ x + a = 0 or 2x - a = 0
⇒ x = -a and x = `a/(2)`.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation by Factorisation method: x2 + 7x + 10 = 0
Solve for x: `(x-3)/(x-4)+(x-5)/(x-6)=10/3; x!=4,6`
Solve the following quadratic equations by factorization:
`(2x)/(x-4)+(2x-5)/(x-3)=25/3`
The sum of the squares of two numbers as 233 and one of the numbers as 3 less than twice the other number find the numbers.
The difference of two numbers is 4. If the difference of their reciprocals is 4/21. Find the numbers.
The sum of a natural number and its square is 156. Find the number.
A two digit number is such that the product of the digits is 12. When 36 is added to this number the digits interchange their places. Determine the number.
Solve the following quadratic equation by factorisation method:
`x/(x + 1) + (x + 1)/x = (34)/(15') x ≠ 0, x ≠ -1`
Mohini wishes to fit three rods together in the shape of a right triangle. If the hypotenuse is 2 cm longer than the base and 4 cm longer than the shortest side, find the lengths of the rods.
4x2 – 9 = 0 implies x is equal to ______.
