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प्रश्न
Solve the following quadratic equation:
ix2 – 4x – 4i = 0
उत्तर
ix2 - 4x - 4i = 0
ax2 + bx + c = 0
a = i, b = -4, c = -4i
Δ = b2 - 4ac
= `(-4)^2 - 4("i")(-4"i")`
= `16 + (4"i")^2`
= 16 + 16i2 ..............[i2 = -1]
= 16 - 16
Δ = 0
Both roots are equal.
x = `(-"b" ± sqrtΔ)/(2"a")`
= `(-"b")/(2"a")`
= `(-(-4))/(2"i")`
= `4/(2"i")`
x = `2/"i"`
= `(2"i")/"i"^2 = -2"i"` .....∵ [i2 = -1]
x = -2i
The roots are -2i, -2i.
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