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प्रश्न
Solve the following set of simultaneous equation.
2x + 3y + 4 = 0; x − 5y = 11
उत्तर १
2x + 3y + 4 = 0 ...(I)
x − 5y = 11 ...(II)
x = 11 + 5y ...(III)
Putting x = 11 + 5y in equation (I)
2(11 + 5y) + 3y = −4
22 + 10y + 3y = −4
22 + 13y = −4
13y = − 4 − 22
13y = −26
y = `−26/13`
y = −2
Putting y = −2 in equation (III)
x = 11 + 5 × (−2)
= 11 + (−10)
x = 1
∴ (x, y) = (1, −2)
उत्तर २
2x + 3y + 4 = 0
∴ 2x + 3y = −4 ...(1)
x − 5y = 11 ...(2)
On multiplying both sides of equation (2) by 2, we get
2x − 10y = 22 ...(3)
By subtracting equation (1) from equation (3), we get
2x − 10y = 22 ...(3)
2x + 3y = - 4 ...(1)
− − +
−13 y = 26
∴ 13y = −26
∴ y = `(−26)/13`
∴ y = −2
Substituting y = −2 in equation (2), we get
∴ x − 5y = 11
∴ x − 5(−2) = 0
∴ x + 10 = 11
∴ x = 11 − 10
∴ x = 1
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