Advertisements
Advertisements
प्रश्न
Solve for x :
`3/(x+1)+4/(x-1)=29/(4x-1);x!=1,-1,1/4`
उत्तर
`3/(x+1)+4/(x-1)=29/(4x-1)`
`=>(3(x-1)+4(x+1))/((x+1)(x-1))=29/(4x-1)`
`=>(3x-3+4x+4)/((x+1)(x-1))=29/(4x-1)`
`=>(7x+1)/(x^2-1)=29/(4x-1)`
⇒(7x+1)(4x−1)=29(x2−1)
⇒28x2+4x−7x−1=29x2−29
⇒28x2−3x−1=29x2−29
⇒x2+3x−28=0
⇒x2+7x−4x−28=0
⇒x(x+7)−4(x+7)=0
⇒(x+7)(x−4)=0
⇒x+7=0 or x−4=0
⇒x=−7 or x=4
APPEARS IN
संबंधित प्रश्न
Two squares have sides x cm and (x + 4) cm. The sum of this areas is 656 cm2. Find the sides of the squares.
A two-digit number is such that the products of its digits is 8. When 18 is subtracted from the number, the digits interchange their places. Find the number?
Solve:
(a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0
Solve the following quadratic equation by
factorisation.
5m2 = 22m + 15
Solve the following quadratic equation by factorisation.
7m2 = 21m
Write the set of value of k for which the quadratic equations has 2x2 + kx − 8 = 0 has real roots.
In each of the following, determine whether the given values are solution of the given equation or not:
2x2 - x + 9 = x2 + 4x + 3; x = 2, x = 3
If the product of two positive consecutive even integers is 288, find the integers.
There are three consecutive positive integers such that the sum of the square of the first and the product of other two is 154. What are the integers?
For quadratic equation `2x + 5/x = 5` :