मराठी

Solve for X and Y: Px + Qy = P – Q, Qx – Py = P + Q - Mathematics

Advertisements
Advertisements

प्रश्न

Solve for x and y:
px + qy = p – q,
qx – py = p + q

उत्तर

The given equations are
px + qy = p – q                                    ………(i)
qx – py = p + q                                    ………(ii)
Multiplying (i) by p and (ii) by q and adding them , we get
`p^2x + q^2x = p^2 – pq + pq + q^2`
`x = (p^2+ q^2)/(p^2+ q^2) = 1`
Substituting x = 1 in (i), we have
p + qy = p – q
⇒qy = -p

⇒y = -1
Hence, x = 1 and y = -1.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Linear Equations in two variables - Exercises 2

APPEARS IN

आर एस अग्रवाल Mathematics [English] Class 10
पाठ 3 Linear Equations in two variables
Exercises 2 | Q 42

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the value of k for which each of the following system of equations has infinitely many solutions :

\[kx + 3y = 2k + 1\]
\[2\left( k + 1 \right)x + 9y = 7k + 1\]


Solve for x and y:
2x – y + 3 = 0, 3x – 7y + 10 = 0


Solve for x and y:

`2x - 3/y = 9, 3x + 7/y = 2`


Show that the system equations
2x - 3y = 5,
6x - 9y = 15

has an infinite number of solutions


Find the value of k for which the system of linear equations has an infinite number of solutions:
kx + 3y = (2k + 1),
2(k + 1)x + 9y = (7k + 1).


The present age of a woman is 3 years more than three times the age of her daughter. Three years hence, the woman’s age will be 10 years more than twice the age of her daughter. Find their present ages.


The sum of two numbers is 80. The larger number exceeds four times the smaller one by 5. Find the numbers.


Find the value(s) of p in (i) to (iv) and p and q in (v) for the following pair of equations:

3x – y – 5 = 0 and 6x – 2y – p = 0,

if the lines represented by these equations are parallel.


If 2x + y = 23 and 4x – y = 19, find the values of 5y – 2x and `y/x` – 2.


Read the following passage:


Lokesh, a production manager in Mumbai, hires a taxi everyday to go to his office. The taxi charges in Mumbai consists of a fixed charges together with the charges for the distance covered. His office is at a distance of 10 km from his home. For a distance of 10 km to his office, Lokesh paid ₹ 105. While coming back home, he took another roµte. He covered a distance of 15 km and the charges paid by him were ₹ 155.

Based on the above information, answer the following questions:

  1. What are the fixed charges?
  2. What are the charges per km?
  3. If fixed charges are ₹ 20 and charges per km are ₹ 10, then how much Lokesh have to pay for travelling a distance of 10 km? 
    OR
    Find the total amount paid by Lokesh for travelling 10 km from home to office and 25 km from office to home. [Fixed charges and charges per km are as in (i) and (ii).

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×