Question

सोपे रूप द्या.

`(a^2 + 10a + 21)/(a^2 + 6a − 7) xx (a^2 − 1)/(a + 3)`

Answer 1

आपणांस माहीत आहे की,

a² − b² = (a + b) (a − b)

a³ − b³ = (a − b)(a² + ab + b²)

`(a^2 + 10a + 21)/(a^2 + 6a − 7) xx (a^2 − 1)/(a + 3)`

= `(a^2 + 7a + 3a + 21)/(a^2 + 7a - a - 7) xx ((a + 1)(a - 1))/(a + 3)`

= `(a(a + 7) + 3(a + 7))/(a(a + 7) - 1(a+7)) xx ((a + 1)(a - 1))/(a + 3)`

= `((a + 7)(a + 3))/((a - 1)(a + 7)) xx ((a + 1)(a - 1))/(a + 3)`

= (a + 1)