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प्रश्न
Specific conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm-1. Calculate its molar conductivity.
बेरीज
उत्तर
`= ("k" xx 1000)/"Molarity"`
`= (0.025 xx 1000)/0.20`
Am = 125 Sm2 mol-1
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Electrolytic Conductance - General Relationship Between
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