Advertisements
Advertisements
प्रश्न
State the formula for calculating length if:
The reading of the main scale is known and the number of vernier scale divisions coinciding with the main scale is known.
उत्तर
If we know the number of vernier scale divisions (V.S.D.) coinciding with the main scale and a number of main scale divisions (M.S.D.) on the left-hand side of zero of vernier scale then Length recorded = Main scale reading + L.C. × V.S.D.
APPEARS IN
संबंधित प्रश्न
Define the term 'Vernier constant'.
State three uses of the vernier callipers.
In the vernier callipers, there are 10 divisions on the vernier scale and 1 cm on the main scale is divided into 10 parts. While measuring the length, the zero of the vernier lies just ahead of the 1.8 cm mark and the 4th division of vernier coincides with a main scale division.
(a) Find the length.
(b) If zero error of vernier callipers is -0.02 cm,
What is the correct length ?
The pitch of a screw gauge is 0.5 mm and the head scale is divided in 100 parts. What is the least count of a screw gauge?
The thimble of a screw gauge has 50 divisions. The spindle advances 1 mm when the screw is turned through two revolutions.
(i) What is the pitch of the screw gauge?
(ii) What is the least count of the screw gauge?
(a) A vernier scale has 20 divisions. It slides over the main scale, whose pitch is 0.5 mm. If the number of divisions on the left hand of the zero of vernier on the main scale is 38 and the 18th vernier scale division coincides with the main scale, calculate the diameter of the sphere, held in the jaws of vernier callipers.
(b) If the vernier has a negative error of 0.04 cm, calculate the corrected radius of the sphere.
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.
What do you understand by the following term as applied to screw gauge?
Positive zero error
