Advertisements
Advertisements
प्रश्न
State whether the following quadratic equation have two distinct real roots. Justify your answer.
`2x^2 - 6x + 9/2 = 0`
उत्तर
The equation `2x^2 - 6x + 9/2` = 0 has real and equal roots.
D = b2 – 4ac
= `(-6)^2 - 4(2)(9/2)`
= 36 – 36
= 0
Hence, the roots are real and equal.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation by using formula method: 5m2 + 5m – 1 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
3x2 + 2x + k = 0
Find the values of k for which the given quadratic equation has real and distinct roots:
kx2 + 2x + 1 = 0
Solve the following quadratic equation using formula method only
`3"x"^2 - 5"x" + 25/12 = 0 `
Solve the following quadratic equation using formula method only
25x2 + 30x + 7 = 0
`sqrt(3)x^2 + 11x + 6sqrt(3)` = 0
Find the discriminant of the following equations and hence find the nature of roots: 3x2 + 2x - 1 = 0
Discuss the nature of the roots of the following quadratic equations : x2 – 4x – 1 = 0
If the difference of the roots of the equation x2 – bx + c = 0 is 1, then:
If the quadratic equation kx2 + kx + 1 = 0 has real and distinct roots, the value of k is ______.
