Advertisements
Advertisements
प्रश्न
Suppose the angles of a triangle are (a − d), a , (a + d) such that , (a + d) >a > (a − d).
उत्तर
\[a - d + a + a + d = 180 \left[ angle sum property \right]\]
\[ \Rightarrow 3a = 180\]
\[ \Rightarrow a = 60\]
\[Now, \left( a + d \right) = 2\left( a - d \right)\]
\[ \Rightarrow a + d = 2a - 2d\]
\[ \Rightarrow a = 3d\]
\[ \Rightarrow d = \frac{60}{3} = 20\]
\[\text{ Therefore, the three angles of a triangle are 40, 60, 80 } .\]
APPEARS IN
संबंधित प्रश्न
If Sn denotes the sum of first n terms of an A.P., prove that S30 = 3[S20 − S10]
In an AP given d = 5, S9 = 75, find a and a9.
The next term of the A.P. \[\sqrt{7}, \sqrt{28}, \sqrt{63}\] is ______.
Find the first term and common difference for the A.P.
5, 1, –3, –7,...
Find the sum of all 2 - digit natural numbers divisible by 4.
The sum of the first n terms of an A.P. is 3n2 + 6n. Find the nth term of this A.P.
The number of terms of the A.P. 3, 7, 11, 15, ... to be taken so that the sum is 406 is
If an = 3 – 4n, show that a1, a2, a3,... form an AP. Also find S20.
The sum of first five multiples of 3 is ______.
Which term of the AP: –2, –7, –12,... will be –77? Find the sum of this AP upto the term –77.