Advertisements
Advertisements
प्रश्न
Suppose the price p and quantity q of a commodity are related by the equation q = 30 - 4p - p2 find
- ed at p = 2
- MR
उत्तर
Given:
q = 30 – 4p – p2
1. ed = (\(\frac { p }{ x }\))(\(\frac { dx }{ dp }\))
If P = 2 then
x = 30 – 4 (2) – 22
= 30 – 8 – 4
=20 – 12
x = 18
\(\frac { dx }{ dp }\) =30 – 4p – p2
= 0 – 4 – 2p
= 0 – 4 – 2 (2)
= -4 -4
= -8
ed = \(\frac { 2 }{ 18 }\) (-8)
x = – \(\frac { 16 }{ 18 }\)
ed = – 0.88
MR
TR = p ×q
TR = p (30 – 4p – p2)
= 30p – 4p2 – p3
MR = \(\frac { d(TR) }{ dp }\)
= 30 – 8p – 3p2
If p = 2
MR = 30 – 8 (2) – 3 (2)2
= 30 – 16 12
MR = 2
APPEARS IN
संबंधित प्रश्न
If x+y = 5 and x-y= 3 then, Value of x
Integration is the reverse process of
Data processing is done by
If 62 = 34 + 4x what is x?
Given the demand function q = 150 − 3p, derive a function for MR.
Find the average cost function where TC = 60 + 10x +15x2
Solve for x quantity demanded if 16x − 4 = 68 + 7x.