Advertisements
Advertisements
प्रश्न
The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.
उत्तर
In group 13 and 14, as we move down the group, the tendency of s-electrons of the valence shell to participate in bond formation decreases. This is due to ineffective shielding of s-electrons of the valence shell by the intervening d- and f-electrons. This is called inert pair effect.
Due to this, s-electrons of the valence shell of group 13 and 14 are unable to participate in bonding. Hence, +1 and +2 oxidation states, in group 13 and 14 respectively, become -more stable with increasing atomic number.
APPEARS IN
संबंधित प्रश्न
Explain the following reaction.
Silicon is heated with methyl chloride at high temperature in the presence of copper.
Elements of group 14 ________.
Classify the following oxide as neutral, acidic, basic or amphoteric:
SiO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO2
Write suitable chemical equations to show the nature of the following oxide.
B2O3
Write suitable chemical equations to show the nature of the following oxide.
CO2
Write suitable chemical equations to show the nature of the following oxide.
Al2O3
Write suitable chemical equations to show the nature of the following oxide.
PbO2
The reason for small radius of Ga compared to Al is:
(i) poor screening effect of d and f orbitals.
(ii) increase in nuclear charge.
(iii) presence of higher orbitals.
(iv) higher atomic number.
A tetravalent element forms monoxide and dioxide with oxygen. When air is passed over heated element (1273 K), producer gas is obtained. Monoxide of the element is a powerful reducing agent and reduces ferric oxide to iron. Identify the element and write formulas of its monoxide and dioxide. Write chemical equations for the formation of producer gas and reduction of ferric oxide with the monoxide.