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प्रश्न
The amplitude and the periodic time of an S.H.M are 5 cm and 6 s respectively. At a distance of 2.5 cm from the mean position, the phase will be:
पर्याय
`π/6`
`π/4`
`(5π)/12`
`π/3`
MCQ
उत्तर
`π/6`
Explanation:
x = a sin ωt or 2.5 = 5 sin`(2π"t")/6`
∴ `(2π"t")/6 = π/6` or t = `1/2 "s"`
The phase difference corresponding to 6 s is 2π.
So, phase difference corresponding to `1/2 "s"`
is `(2π)/12`
i.e.,
`π/6`
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Graphical Representation of S.H.M.
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