Question

The average K.E. of hydrogen molecules at 27° C is E. The average K.E. at 627° C is ____________.

पर्याय

• 3 K.E.

• `sqrt2` K.E.

• 2 K.E.

• 4 K.E.

Answer 1

The average K.E. of hydrogen molecules at 27° C is E. The average K.E. at 627° C is 3 K.E.

Explanation:

K.E._av = `3/2`K_BT

`therefore` K.E._av `prop` T

` therefore "K.E."_2/ "K.E."_1 = T_2/T_1 = 900/300` = 3

`therefore "K.E."_2 = 3"K.E."_1` = 3 K.E.