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प्रश्न
The button cell used in watches functions as follows.
\[\ce{Zn_{(s)} + Ag2O_{(s)} + H2O_{(l)} ⇌ 2Ag_{(s)} + Zn^{2+}_{( aq)} + 2OH^-_{( aq)}}\] the half cell potentials are \[\ce{Ag2O_{(s)} + H2O_{(l)} + 2e^- -> 2Ag_{(s)} + 2OH^-_{( aq)}}\] E0 = 0.34 V The cell potential will be
पर्याय
0.84 V
1.34 V
1.10 V
0.42 V
उत्तर
1.10 V
Explanation:
Anodic oxidation: (Reverse the given reaction)
\[\ce{(E^0_{ox})}\] = 0 76. cathodic reduction
∴ \[\ce{E^0_{cell} = (E^0_{ox}) + (E^0_{red})}\]
= 0.76 + 0.34
= 1.1 V
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