Question

The compressibility of water is 5 × 10^-10 m²/N. Pressure of 15 × 10⁶ Pa is applied on 100 ml volume of water. The change in the volume of water is ______.

पर्याय

• zero

• 0.75 ml decrease

• 0.75 ml increase

• 1.50 ml increase

Answer 1

The compressibility of water is 5 × 10^-10 m²/N. Pressure of 15 × 10⁶ Pa is applied on 100 ml volume of water. The change in the volume of water is 0.75 ml decrease.

Explanation:

The compressibility of water is given by

K = `(- Delta "V")/(Delta "pV")`

⇒ Δ V = - KΔpV

= - (5 × 10^-10 × 15 × 10⁶ × 100)

= - 0.75 ml decrease

Thus, volume of water is decreased by 0.75 ml.