Question

The CORRECT decreasing order for the stability of carbanion.

पर्याय

• \[\ce{CH\bond{3}\overset{\text{___}}{\overset{\bullet\phantom{.}\bullet}{C}}> CH2 =\overset{\text{___}\phantom{....}}{\overset{\bullet\phantom{.}\bullet}{C}H}> CH3 -\overset{\text{___}\phantom{......}}{\overset{\bullet\phantom{.}\bullet}{C}H2}}\]

• \[\ce{CH2 = \overset{\text{___}\phantom{....}}{\overset{\bullet\phantom{.}\bullet}{C}H}> CH \bond{3}\overset{\text{___}\phantom{}}{\overset{\bullet\phantom{.}\bullet}{C}}> CH3 -\overset{\text{___}\phantom{......}}{\overset{\bullet\phantom{.}\bullet}{C}H2}}\]

• \[\ce{CH3 - \overset{\text{___}\phantom{......}}{\overset{\bullet\phantom{.}\bullet}{C}H2}> CH2 = \overset{\text{___}\phantom{....}}{\overset{\bullet\phantom{.}\bullet}{C}H}> CH \bond{3}\overset{\text{___}\phantom{}}{\overset{\bullet\phantom{.}\bullet}{C}}}\]

• \[\ce{CH3 - \overset{\text{___}\phantom{......}}{\overset{\bullet\phantom{.}\bullet}{C}H2}> CH \bond{3} \overset{\text{___}\phantom{}}{\overset{\bullet\phantom{.}\bullet}{C}}> CH2 =\overset{\text{___}\phantom{....}}{\overset{\bullet\phantom{.}\bullet}{C}H}}\]

Answer 1

\[\ce{CH\bond{3}\overset{\text{___}}{\overset{\bullet\phantom{.}\bullet}{C}}> CH2 =\overset{\text{___}\phantom{....}}{\overset{\bullet\phantom{.}\bullet}{C}H}> CH3 -\overset{\text{___}\phantom{......}}{\overset{\bullet\phantom{.}\bullet}{C}H2}}\]

Explanation:

The stability of carbanion increases with increase in percentage s-character.

(sp hybridization): % s-character: 50%

\[\ce{CH\bond{3}\overset{\text{___}\phantom{}}{\overset{\bullet\phantom{.}\bullet{}}{C}}}\]

(sp² hybridization): % s-character: 33.3%

\[\ce{CH2=\overset{\text{___}\phantom{....}}{\overset{\bullet\phantom{.}\bullet}{C}H}}\]

(sp³ hybridization): % s-character: 25%

\[\ce{CH3-\overset{\text{___}\phantom{......}}{\overset{\bullet\phantom{.}\bullet}{C}H2}}\]