Question

The correct order of bond dissociation enthalpy of halogens is ______.

पर्याय

• \[\ce{Cl2 > Br2 > F2 > I2}\]

• \[\ce{F2 > Cl2 > Br2 > I2}\]

• \[\ce{Cl2 > F2 > Br2 > I2}\]

• \[\ce{I2 > Br2 > Cl2 > F2}\]

Answer 1

The correct order of bond dissociation enthalpy of halogens is \[\underline{\ce{Cl2 > Br2 > F2 > I2}}\].

Explanation:

The energy needed to sever an atom-to-atom bond is referred to as bond dissociation energy. The strength of the ties affects how much it is worth. The binding strength and dissociation energy of an atom decrease with increasing size. Hence, as the size of the group grows, the dissociation energy drops. Due to the small size of F in the halogen family, it experiences high electron repulsion between its electrons, which weakens its bond and lowers its dissociation energy.