Advertisements
Advertisements
प्रश्न
The cost of a notebook is Rs. 10ab. If Babu has Rs. (5a2b + 20ab2 + 40ab). Then how many notebooks can he buy?
उत्तर
For Rs. 10ab the number of notebooks can buy = 1.
For Rs. (5a2b + 20ab2 + 40ab) the number of notebooks can buy = `"Total amount"/"cost of 1 notebook"`
= `(5"a"^2"b" + 20"ab"^2 + 40"ab")/(10"ab")`
= `(5"a"^2"b")/(10"ab") + (20"ab"^2)/(10"ab") + (40"ab")/(10"ab")`
= `1/2 "a"^(2-1) "b"^(1-1) + 2"a"^(1-1) "b"^(2-1) + 4"a"^(1-1) "b"^(1-1)`
= `1/2 "a"^1 "b"^0 + 2"a"^0"b"^1 + 4"a"^0"b"^0`
Number of notebook he can buy = `1/2"a" + 2"b" + 4`
APPEARS IN
संबंधित प्रश्न
Carry out the following division:
28x4 ÷ 56x
Carry out the following divisions:
−36y3 ÷ 9y2
Carry out the following divisions:
12a8b8 ÷ (−6a6b4)
Divide: 24x3y3 by −8y2
Divide: −24x4d3 by −2x2d5
`(42"a"^4"b"^5(_))/(6"a"^4"b"^2)` = `(_)"b"^((_))"c"^2`
Divide x3y2 by x2y
Divide (3xy)2 by 9xy
Simplify `(3"m"^2)/"m" + (2"m"^4)/("m"^3)`
What sum of money will earn ₹ 500 as simple interest in 1 year at 5% per annum?