Question

The Coulomb force (F) versus (1/r²) graphs for two pairs of point charges (q₁ and q₂) and (q₂ and q₃) are shown in figure. The charge q₂ is positive and has least magnitude. Then:

पर्याय

• q₁ > q₂ > q₃

• q₁ > q₃ > q₂

• q₃ > q₂ > q₁

• q₃ > q₁ > q₂

Answer 1

q₃ > q₁ > q₂

Explanation:

`tantheta = F/(1//r^2)`

F . r² = tan θ

We have, `F = (Kq_1q_2)/r^2`

F r² = Kq₁q₂

∴ Kq₁q₂ = tan θ₁   ...(i)

and Kq₂q₃ = tan θ₂   ...(ii)

`q_1/q_3 = (tantheta_1)/(tantheta_2)`

⇒ `q_3 = q_1(tantheta_2)/(tantheta_1)`

From the figure, θ₂ is more than θ₁.

So, q₃ will be more than q₁.

Since the charge q₂ has the least magnitude, the decreasing order of magnitude of charges will be q₃ > q₁ > q₂.