Question

The de Broglie wavelength of a car of mass 1000 kg and velocity 36 km/hr is :

पर्याय

• 6.626 × 10^–34 m

• 6.626 × 10^–38 m

• 6.626 × 10^–31 m

• 6.626 × l0^–30 m

Answer 1

6.626 × 10^–38 m

Explanation:

`lambda = h/(mv)`

h = 6.6 × 10^–34 J/s

m = 1000 kg

v = 36 km/hr = `(36 xx 10^3)/(60 xx 60)` m/sec = 10 m/sec

∴ `lamda = (6.6 xx 10^(-34))/(10^3 xx 10)` = 6.6 × 10^–38 m