Question

The de Broglie wavelength of an electron in the 4^th Bohr orbit is ______.

पर्याय

• 2πa₀

• 4πa₀

• 6πa₀

• 8πa₀

Answer 1

The de Broglie wavelength of an electron in the 4^th Bohr orbit is 8πa₀.

Explanation:

2πr = nλ

r = `("n"^2"a"_0)/"Z"`

`2π xx 4^2/1"a"_0` = 4λ

⇒ λ = `2π xx 4/1"a"_0`

⇒ λ = 8πa₀