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प्रश्न
The differential equation whose solution is y = Aex + Be-x, is
पर्याय
`("d"^2"y")/"dx"^2` + y = 0
`("d"^2"y")/"dx"^2` - y = 0
`"dy"/"dx"` + y = 0
`"dy"/"dx"` - y = 0
MCQ
उत्तर
`("d"^2"y")/"dx"^2` - y = 0
Explanation:
y = Aex + Be-x ....(i)
`=> "dy"/"dx"` = Aex - Be-x
`=> ("d"^2"y")/"dx"^2` = Aex + Be-x
= y ...[from (i)]
∴ `("d"^2"y")/"dx"^2` - y = 0
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Solution of a Differential Equation
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