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प्रश्न
The diverging lens in part (a) is replaced by a converging lens also of focal length 100 mm. The object remains in the same position and an image is formed by the converging lens. Compare two properties of this image with those of the image formed by the diverging lens in part (a).
उत्तर
| S.No | Image formed by a diverging lens | Image formed by a converging lens |
| 1 | Image formed is virtual and erect | Image formed is real and inverted |
| 2 | Image is smaller in size than the object | Image is larger in size than the object |
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संबंधित प्रश्न
Match the items given in Column I with one or more items of Column II.
| Column I | Column II | ||
| (a) | A plane mirror | (i) | Used as a magnifying glass. |
| (b) | A convex mirror | (ii) | Can form image of objects spread over a large area. |
| (c) | A convex lens | (iii) | Used by dentists to see enlarged image of teeth. |
| (d) | A concave mirror | (iv) | The image is always inverted and magnified. |
| (e) | A concave lens | (v) | The image is erect and of the same size as the object. |
| (vi) | The image is erect and smaller in size than the object. |
A 50 cm tall object is at a very large distance from a diverging lens. A virtual, erect and diminished image of the object is formed at a distance of 20 cm in front of the lens. How much is the focal length of the lens?
Discuss the position and nature of image formed by a convex mirror when an object is moved from infinity towards the pole of mirror.
How will you distinguish between a plane mirror, a concave mirror and a convex mirror, without touching them?
Upto what maximum distance from the pole the image in a convex mirror can be obtained? what will be the location of object then ?
An object 5 cm high forms a virtual image of 1.25 cm high, when placed in front of a convex mirror at a distance of 24 cm. Calculate:
- the position of the image
- the focal length of the convex mirror.
The image formed in a plane mirror is always inverted.
