मराठी

The electric field in a plane electromagnetic wave is given by radE→=200cos[(0.5×103m)x-(1.5×1011rads×t)]Vmj^. If the wave falls normally on a perfectly reflecting surface having an area -

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प्रश्न

The electric field in a plane electromagnetic wave is given by `vecE = 200cos[((0.5 xx 10^3)/m)x - (1.5 xx 10^11 "rad"/s xx t)]V/mhatj`. If the wave falls normally on a perfectly reflecting surface having an area of 100 cm2. If the radiation pressure exerted by the E.M. wave on the surface during a 10-minute exposure is `x/10^9 N/m^2`. Find the value of x.

पर्याय

  • 350

  • 351

  • 354

  • 355

MCQ

उत्तर

354

Explanation:

We can find the required parameter and then use the formula by comparing the given equation with E = E0 cos(kx - wt).

Radiation pressure = `21/c`

and `I = 1/2ε_0E_0^2c`

Radiation Pressure = `21/c = (2/c)(1/2ε_0E_0^2c) = ε_0E^2`

Here, E = 200 `V/m` and `ε_0 = 8.85 xx 10^-12`

Radiation Pressure = `8.85 xx 10^-12 xx (200)^2`

= `354.0 xx 10^-9 "N""/""m"^2`

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