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प्रश्न
The electron in the hydrogen atom is moving with a speed of 1.5 x 106 m/s in an orbit of radius 2 Å. Magnetic moment of the revolving electron is ____________.
पर्याय
10-20 Am2
2.4 x 10-23 Am2
10-23 Am2
3.2 x 10-19 Am2
MCQ
रिकाम्या जागा भरा
उत्तर
The electron in the hydrogen atom is moving with a speed of 1.5 x 106 m/s in an orbit of radius 2 Å. Magnetic moment of the revolving electron is 2.4 x 10-23 Am2.
Explanation:
Tue magnetic moment of the revolving electron is
`"M" = "IA" = e/"T" xx pi"r"^2 "But T" = (2pi"r")/"v"`
`therefore "M" = "ev"/(2pi"r") xx pi"r"^2`
` = "evr"/2`
`therefore "M" = (1.6 xx 10^-19 xx 1.5 xx 10^6 xx 2 xx 0^-10)/(2)`
`=2.4 xx 10^23 "Am"^2`
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