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प्रश्न
The energies E1 and E2 of the two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths ie λ1 and λ2 will be
पर्याय
`λ_1/λ_2` = 1
λ1 = 2λ2
λ1 = `sqrt(25 xx 50)` λ2
2λ1 = λ2
उत्तर
λ1 = 2λ2
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