Question

The energy of an electron in the first Bohr orbit of the H-atom is −13.6 eV. The energy value of an electron in the excited state of Li²⁺ is ______.

पर्याय

• −27.2 eV

• 30.6 eV

• −30.6 eV

• 27.2 eV

Answer 1

The energy of an electron in the first Bohr orbit of the H-atom is −13.6 eV. The energy value of an electron in the excited state of Li²⁺ is −30.6 eV.

Explanation:

For Li²⁺ ion,

E = `-13.6 xx "Z"^2/"n"^2 "eV"`

= `-13.6 xx (3)^2/(2)^2`

= `(-13.6 xx 9)/4`

= −30.6 eV