मराठी

The equation of stationary wave on a string clamped at both ends and vibrating in the third harmonic is given by y = 0.5 sin (0.314 x) cos (600 πt), where x and y are in cm and t in second. -

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प्रश्न

The equation of stationary wave on a string clamped at both ends and vibrating in the third harmonic is given by y = 0.5 sin (0.314 x) cos (600 πt), where x and y are in cm and t in second. The length of the vibrating string is ______
(π = 3.14) 

पर्याय

  • 15 cm

  • 40 cm

  • 10 cm

  • 30 cm

MCQ
रिकाम्या जागा भरा

उत्तर

The equation of stationary wave on a string clamped at both ends and vibrating in the third harmonic is given by y = 0.5 sin (0.314 x) cos (600 πt), where x and y are in cm and t in second. The length of the vibrating string is 30 cm.
(π = 3.14) 

Explanation:

y = 0.5 sin (0.314 x) cos (600 πt)

0.314 x = `2pi x/lambda`

`lambda = (2pi)/3.14 = (2 xx 3.14)/(0.314)` = 20 cm

The string is vibrating in third harmonic, forming three loops.

∴ Length of string = `3. lambda/2 = (3 xx 20)/2 = 30` cm

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