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प्रश्न
The equation of tangent at P(- 4, - 4) on the curve x2 = - 4y is ______.
पर्याय
2x - y + 4 = 0
2x + y - 4 = 0
3x - y + 8 = 0
2x + y + 4 = 0
MCQ
रिकाम्या जागा भरा
उत्तर
The equation of tangent at P(- 4, - 4) on the curve x2 = - 4y is 2x - y + 4 = 0.
Explanation:
We know that equation of tangent of curve
x2 = 4 y at (x1, y1) is
xx1 = 2(y + y1)
∴ Equation of tangent of curve x2 = - 4y at (-4, -4) is
- 4x = - 2(y - 4)
⇒ 2x = y - 4
⇒ 2x - y + 4 = 0
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Application of Differential Equations
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