Question

The equation of the circle with centre (4, 5) which passes through (7, 3) is ______.

पर्याय

• x² + y² - 8x + 10y - 77 = 0

• x² + y² - 6x - 8y + 24 = 0

• x² + y² - 8x - 10y + 28 = 0

• x² + y² - 8x - 10y - 23 = 0

Answer 1

The equation of the circle with centre (4, 5) which passes through (7, 3) is x² + y² - 8x - 10y + 28 = 0.

Explanation:

Centre (4, 5) and

r = `sqrt((7 - 4)^2 + (3 - 5)^2)`

`= sqrt13`

Hence, required equation is

(x - 4)² + (y - 5)² = `(sqrt13)^2`

⇒ x² + y² - 8x - 10y + 28 = 0