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प्रश्न
The escape velocity of a body from the surface of the earth is 11.2 km/s. If a satellite were to orbit close to the surface, what would be its critical velocity?
उत्तर
Escape velocity of body from the surface of the earth = 11.2 km/s
`v_e=sqrt2v_0`
`v_0=v_e/sqrt2`
`v_0=(11.2xx10^3)/1.414`
v0 = 7.92×103 m/s or 7.92 km/s
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संबंधित प्रश्न
Determine the binding energy of satellite of mass 1000 kg revolving in a circular orbit around the Earth when it is close to the surface of Earth. Hence find kinetic energy and potential energy of the satellite. [Mass of Earth = 6 x 1024 kg, radius of Earth = 6400 km; gravitational constant G = 6.67 x 10-11 Nm2 /kg2 ]
Find the total energy and binding energy of an artificial satellite of mass 800 kg orbiting at a height of 1800 km above the surface of the earth.
[G = 6.67 x 10-11 S.I. units, Radius of earth : R = 6400 km, Mass of earth : M = 6 x 1024 kg]
Define binding energy and obtain an expression for binding energy of a satellite revolving in a circular orbit round the earth.
