Question

The first ionization energy of H is 21.79 × 10^-19 J. The second ionization energy of He atom is ______ × 10^-19J.

पर्याय

• 87.16

• 52.69

• 45.23

• 0.001

Answer 1

The first ionization energy of H is 21.79 × 10^-19 J. The second ionization energy of He atom is 87.16 × 10^-19J.

Explanation:

IP = `13.6 xx "Z"^2/"n"^2` = IP of H `xx "Z"^2/"n"^2`

He = `21.79 xx 10^-19 xx "Z"^2/1^2`

= 87.16 × 10^-19J