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प्रश्न
The floor of a room is 8 m 96 cm long and 6 m 72 cm broad. Find the minimum number of square tiles of the same size needed to cover the entire floor.
उत्तर
Length of floor of a room = 8 m 96 cm = 896 cm
Breadth of floor of the room = 6 m 72 cm = 672 cm
To find the minimum number of square tiles of same size needed to cover the entire floor, we find the LCM of 896 cm and 672 cm.
2 |
672, 896 |
2 |
336, 448 |
2 |
168, 224 |
2 |
84, 112 |
2 |
42, 56 |
2 |
21, 28 |
2 |
21, 14 |
3 |
21, 7 |
7 |
7, 7 |
1, 1 |
∴ LCM of 672 and 896 is 2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 7 = 2688
∴ Number of square titles = `(2688/672 xx 2688/896)`
= `4 xx 3` = 12
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