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प्रश्न
The function f(x) = tan-1 x is ____________.
पर्याय
strict increasing
differentiable nowhere
strictly decreasing
neither increasing nor decreasing
MCQ
रिकाम्या जागा भरा
उत्तर
The function f(x) = tan-1 x is strict increasing.
Explanation:
`"f'" ("x") = "d"/"dx" ("tan"^-1 "x") = 1/(1 + "x"^2) > 0 AA "x" in "R".`
Therefore, f is strictly increasing on R.
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