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प्रश्न
The gravitational force of attraction between two objects is x. Keeping the masses of the objects unchanged, if the distance between the objects is halved, then the magnitude of gravitational force between them will become :
पर्याय
x/4
x/2
2x
4x
उत्तर
4x
G = x
m1 and m2 are constant
Since, r is reduced to half, let, r/ = r/2
Gravitation force, F = G × m1 × m2/r2 = x
When r is reduced to half the force becomes, F/ = G × m1 × m2/(r/)2
= G × m1 × m2 /(r/2)2
= 4x
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