Question

The heat of neutralization for the reaction KOH + HNO₃ ⇌ KNO₃ + H₂O When 0.5 mole of HNO₃ is mixed with 0.2 moles of KOH is:

पर्याय

• + 57.lkJ

• – 11.4kJ

• + 11.4kJ

• + 28.5kJ

Answer 1

– 11.4kJ

Explanation:

KOH + HNO₃ ⇌ KNO₃ + H₂O

When 0.5 mol of HNO₃ is mixed with 0.2 mol of KOH, only 0.2 mol of HNO₃ reacts with KOH.

1 mol of KOH reacts with 1 mol of HNO₃ and produces 57.1 KJ of heat.

∴ When 0.2 mol of HNO₃ reacts with 0.2 mol of KOH, heat produced 

= – 57.l × 0.2KJ

= – 11.4kJ