Question

The horizontal component of earth’s magnetic field at a place is `sqrt3` times the vertical component. The angle of dip at that place is ______.

पर्याय

• π/6

• π/3

• π/4

• 0

Answer 1

The horizontal component of earth’s magnetic field at a place is `sqrt3` times the vertical component. The angle of dip at that place is π/6.

Explanation:

Target law B_v = B_H tan δ

`tan δ = "B"_"v"/"B"_"H"`

Given `"B"_"H" = sqrt3 "B"_"v"`

`tan δ = "B"_"v"/(sqrt3 "B"_"v") = 1/sqrt3`

`δ = 30^circ or pi/6` radians.