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प्रश्न
The integrating factor of linear differential equation `dy/dx+ysecx=tanx` is
(a)secx- tan x
(b) sec x · tan x
(c)sex+tanx
(d) secx.cotx
उत्तर
`dy/dx+P.y=Q`
therefore P=secx
`I.f=e^(intsecxdx)=e^(log|sex+tanx|)`
=secx+tanx
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