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प्रश्न
The interaction energy of London force is inversely proportional to sixth power of the distance between two interacting particles but their magnitude depends upon
पर्याय
Charge of interacting particles
Mass of interacting particles
Polarisability of interacting particles
Strength of permanent dipoles in the particles
उत्तर
Polarisability of interacting particles
Explanation:
London dispersion forces operate only over very short distance. The energy of interaction varies as
1/(distance between two interacting particles)6 Large or more complex are the molecules, greater is the magnitude of London forces. This is obviously due to the fact that the large electron clouds are easily distorted or polarised.
Hence, greater the polarisability of the interacting particles, greater is the magnitude of the interaction energy.
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संबंधित प्रश्न
Use the information and data given below:
• Stronger intermolecular forces result in higher boiling point.
Which type of intermolecular forces are present in the molecules \[\ce{HF, HCl, HBr and HI}\]?
Use the information and data given below:
• Strength of London forces increases with the number of electrons in the molecule.
Looking at the trend of boiling points of \[\ce{HCl, HBr and HI}\], explain out of dipole-dipole interaction and London interaction, which one is predominant here.
______ interaction is predominant between a polar molecule having permanent dipole moment and non-polar molecule with zero dipole moment.
The interaction energy of London forces between two particles is proportional to rx, where r is the distance between the particles. The value of x is ______.
The predominant intermolecular forces present in ethyl acetate, a liquid, are ______.
