Question

The IUPAC name of the following compound.

\[\begin{array}{cc}
\phantom{.}\ce{CH(CH3)2}\\
|\phantom{........}\\
\ce{CH3 - CH2 - CH2 - CH - CH - CH2 - CH - CH2}\\
\phantom{............................}|\phantom{...................}|\phantom{...}\\
\phantom{...........................}\ce{CH2CH3}\phantom{...........}\ce{CH3}\phantom{}
\end{array}\]

पर्याय

• 4, 5-di(1-Methylethyl)decane

• 5-Ethyl-4-(1-methylethyl)decane

• 6-(1-Methylethyl)-5-ethyldecane

• 5-Ethyl-4-propyldecane

Answer 1

5-Ethyl-4-(1-methylethyl)decane

Explanation:

The numbering of the longest carbon chain is as follows:

\[\begin{array}{cc}
\ce{H3C - CH - CH3}\phantom{..............}\\
|\phantom{................}\\
\ce{^1CH3 - ^2CH2 - ^3CH2 - ^4CH - ^5CH - ^6CH2 - ^7CH - ^8CH2 - ^9CH2}\\
\phantom{................................}|\phantom{...............................}|\phantom{}\\
\phantom{.....................................}\ce{CH2 - CH3}\phantom{..................}\ce{^10CH3}\phantom{...}
\end{array}\]

There are ten carbon atoms in the longest chain. On carbon 5, one ethyl substituent is present, and on carbon 4, one complex substituent (1-methylethyl) is present. As a result, the compound's name is 5-Ethyl-4-(1-methylethyl)decane.