Question

The kinetic energy of electron in (electron volt) moving with the velocity of 4 × 10⁶ m/s will be

पर्याय

• 30 ev

• 45 ev

• 50 ev

• 60 ev

Answer 1

45 ev

Explanation:

K.E = `1/2` mv² = `1/2 xx (9 xx 10^-31 xx (4 xx 10^6)^2)/(1.6 xx 10^-19)` ev = 45 ev