मराठी

The least count of a vernier callipers is 0.01 cm and it has an error of + 0.07 cm. While measuring the radius of a sphere, the main scale reading is 2.90 cm and the 5th vernier scale - Physics

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प्रश्न

The least count of a vernier callipers is 0.01 cm and it has an error of + 0.07 cm. While measuring the radius of a sphere, the main scale reading is 2.90 cm and the 5th vernier scale division coincides with the main scale. Calculate the correct radius.

संख्यात्मक

उत्तर

Least count (L.C.) = 0.01 cm
Error = + 0.07 cm
Correction = (Error) = – (+ 0.07) = – 0.07 cm
Main scale reading = 2.90 cm
Vernier scale division (V.S.D.) coinciding with main scale = 5th Observed diameter of sphere = Main scale reading + L.C. × V.S.D.
= 2.90 + 0.01 × 5
= 2.90 + 0.05
= 2.95 cm
Corrected diameter = Observed diameter + Correction
= 2.95 + (−0.07)
= 2.95 – 0.07
= 2.88 cm
∴ Corrected radius = 2.88/2 = 1.44 cm

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Vernier Callipers
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पाठ 1: Measurements and Experimentation - Unit 3 Practice Problems 4

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics Part 1 [English] Class 9
पाठ 1 Measurements and Experimentation
Unit 3 Practice Problems 4 | Q 2

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