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प्रश्न
The line 3x + y – 9 = 0 divides the line joining the points (1, 3) and (2, 7) internally in the ratio ______.
पर्याय
3 : 4
3 : 2
2 : 3
4 : 3
MCQ
रिकाम्या जागा भरा
उत्तर
The line 3x + y – 9 = 0 divides the line joining the points (1, 3) and (2, 7) internally in the ratio 3 : 4.
Explanation:
Let the line 3x + y – 9 = 0 divide the line segment joining A(l, 3) ad B(2, 7) in the ratio K : 1 at point C.
The coordinates of C are `((2"K" + 1)/("K + 1")) + ("7K" + 3)/("K + 1")`
But the point C lies on the line 3x + y - 9 = 0
`therefore 3((2"K" + 1)/("K + 1")) + ("7K" + 3)/("K + 1") - 9 = 0`
⇒ 6K + 3 + 7K + 3 - 9 - 9K = 0
⇒ 4K - 3 = 0
⇒ K = `3/4`
∴ Required ratio = 3 : 4
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