Advertisements
Advertisements
प्रश्न
The line through the points (– 2, a) and (9, 3) has slope `-1/2` Find the value of a.
उत्तर
The given points are (– 2, a) and (9, 3)
Slope of a line = `(y_2 -y_1)/(x_2 - x_1)`
`-1/2 =(3 - "a")/(9 + 2)`
⇒ `-1/2 = (3 -"a")/11`
2(3 – a) = – 11
⇒ 6 – 2a = – 11
– 2a = – 11 – 6
⇒ – 2a = – 17
⇒ a = `(-17)/(-2)`
∴ The value of a = `17/2`
APPEARS IN
संबंधित प्रश्न
What is the slope of a line whose inclination with positive direction of x-axis is 90°
What is the slope of a line whose inclination with positive direction of x-axis is 0°
What is the inclination of a line whose slope is 1
What is the slope of a line perpendicular to the line joining A(5, 1) and P where P is the mid-point of the segment joining (4, 2) and (–6, 4).
The line through the points (– 2, 6) and (4, 8) is perpendicular to the line through the points (8, 12) and (x, 24). Find the value of x.
Show that the given points form a right angled triangle and check whether they satisfy Pythagoras theorem
A(1, – 4), B(2, – 3) and C(4, – 7)
A quadrilateral has vertices at A(– 4, – 2), B(5, – 1), C(6, 5) and D(– 7, 6). Show that the mid-points of its sides form a parallelogram.
The slope of the line which is perpendicular to a line joining the points (0, 0) and (− 8, 8) is
If slope of the line PQ is `1/sqrt(3)` then slope of the perpendicular bisector of PQ is
Find the equation of a line passing through the point of intersection of the lines 4x + 7y – 3 = 0 and 2x – 3y + 1 = 0 that has equal intercepts on the axes.
