Question

The lowest frequency of light that will cause the emission of photoelectrons from the surface of a metal (for which work function is 1.65 eV) will be ____________.

पर्याय

• 4 x 10¹⁰ Hz

• 4 x 10¹¹ Hz

• 4 x 10¹⁴ Hz

• 4 x 10^-10 Hz

Answer 1

The lowest frequency of light that will cause the emission of photoelectrons from the surface of a metal (for which work function is 1.65 eV) will be 4 x 10¹⁴ Hz.

Explanation:

`"Minimum frequency:"  phi = "hv"_0`

`therefore "v"_0 = phi/"h"`

`= (1.65 xx 1.6 xx 10^-19)/(6.63 xx 10^-34) approx 4 xx 10^14  "Hz"`