मराठी

The magnetic flux through a coil perpendicular to its plane is varying according to the relation Φ = (5t3 + 4t2 + 2t - 5) Weber. If the resistant of the coil is 5 ohm, -

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प्रश्न

The magnetic flux through a coil perpendicular to its plane is varying according to the relation Φ = (5t3 + 4t2 + 2t - 5) Weber. If the resistant of the coil is 5 ohm, then the induced current through the coil at t = 2 sec will be ______.

पर्याय

  • 15.6 A

  • 16.6 A

  • 17.6 A

  • 18.6 A

MCQ
रिकाम्या जागा भरा

उत्तर

The magnetic flux through a coil perpendicular to its plane is varying according to the relation Φ = (5t3 + 4t2 + 2t - 5) Weber. If the resistant of the coil is 5 ohm, then the induced current through the coil at t = 2 sec will be 15.6 A.

Explanation:

Φ = (5t3 + 4t2 + 2t - 5)

|e| = 15t2 + 8t + 2     `[∵ |"e"| = ("d"phi)/"dt" ]`

R = 5Ω

So, i = `|"e"|/"R"=(15"t"^2+8"t"+2)/5`

= 3t2 + 1.6t + 0.4

= 3.22 + 1.6 × 2 + 0.4 

= 15.6 A  (∵ t = 2 sec) 

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