Advertisements
Advertisements
प्रश्न
The marks obtained by 10 candidates in English and Mathematics are given below:
| Marks in English | 20 | 13 | 18 | 21 | 11 | 12 | 17 | 14 | 19 | 15 |
| Marks in Mathematics | 17 | 12 | 23 | 25 | 14 | 8 | 19 | 21 | 22 | 19 |
Estimate the probable score for Mathematics if the marks obtained in English are 24.
उत्तर
Here n = 10.
Take the marks obtained in English and Mathematics as x and y respectively.
Let for x assumed mean be 17 and for v assumed mean be 19.
We construct the table as follows:
r = `(∑uv - 1/n ∑u ∑v)/(sqrt(∑u^2 - 1/n (∑u)^2) sqrt(∑v^2-1/n (∑v)^2)`
r = ` (135 - 1/10 (10 xx 10) )/(sqrt(120-1/10 (10)^2) sqrt(264-1/10 (10)^2)`
r = `(125)/(sqrt110 . sqrt254) = 0.7478`
Now, `b_(yx) = (∑uv - 1/n ∑u ∑v)/(∑u^2 - 1/n (∑u)^2) = (135 - 10)/(120 - 10) = (125)/(110) = (25)/(22) `
Here, `barx = 17 + ((-10))/10 = 16`
`bary = 19 + ((-10))/10 = 18`
Since marks obtained in English i.e., x = 24 is given
Now, using regression line of y on x : `(y - bary) = b_(yx) (x - barx)`
y - 18 = `(25)/(22) (x - 16)`
⇒ 22y - 396 = 25x - 400
For 22y = 25x - 4
⇒ 22y = 25 x 24 -4
y = `(596)/(22)` = 27.09 = 27 marks approx
Probable marks of mathematics is 27, when marks obtained in English are 24.
APPEARS IN
संबंधित प्रश्न
The two lines of regressions are 4x + 2y- 3 = 0 and 3x + 6y + 5 =0. Find the correlation co-efficient between x and y.
In a contest, the competitors are awarded marks out of 20 by two judges. The scores of the 10 competitors are given below. Calculate Spearman's rank correlation.
| Competitors | A | B | C | D | E | F | G | H | I | J |
| Judge A | 2 | 11 | 11 | 18 | 6 | 5 | 8 | 16 | 13 | 15 |
| Judge B | 6 | 11 | 16 | 9 | 14 | 20 | 4 | 3 | 13 | 17 |
Examine whether the following statement pattern is tautology, contradiction or contingency :
p ∨ – (p ∧ q)
Bring out the inconsistency; if any: byx + bxy = 1.30. and r = 0.75
Two samples from bivariate populations have 15 observations each. The sample mean of X and Y are 25 and 18 respectively. The corresponding sum of squares of deviations from means are 136 and 148. The sum of product of deviations from respective means is 122. Obtain the equation of line of regression of X on Y.
For 50 students of a class, the regression equation of marks in statistics (X) on the marks in accountancy (Y) is 3y – 5x + 180 = 0. The mean marks in accountancy is 44 and the variance of marks in statistics is `(9/16)^(th)` of the variance of marks in accountancy. Find the mean marks in statistics and the correlation coefficient between marks in the two subjects.
Bring out the inconsistency, if any in the following :
bYX = 1.9 and bXY = -0.25
For a bivariate data,
`bar x = 53 , bar y = 28 , "b"_"yx"=-1.5 and "b"_"xy"=- 0.2` Find Estimate of X for y = 25.
From the two regression equations y = 4x - 5 and 3x = 2y + 5, find `barx and bary`
From the data 7 pairs of observations on X and Y following results are obtained :
∑(xi - 70) = - 38 ; ∑ (yi - 60) = - 5 ;
∑ (xi - 70)2 = 2990 ; ∑ (yi - 60)2 = 475 ;
∑ (xi - 70) (yi - 60) = 1063
Obtain :
(a) The line of regression of Y on X.
(b) The line of regression of X on Y.
Values of two regression coefficients between the variables X and Y are `b_"yx" = - 0.4` and `b_"xy"` = - 2.025 respectively. Obtain the value of correlation coefficient.
For the two regression equations 4y = 9x + 15 and 25x = 6y + 7 find correlation coefficient r, `barx, bary`
Let X be the number of matches played by the player and Y he the number of matches in which he scored more thun 50 runs. The following data is obtained for 5 players :
| No. of Matches Played (X) | Data of matches of 5 players | ||||
| 21 | 25 | 26 | 24 | 19 | |
| Scored more than 50 in a match (Y) | 19 | 20 | 24 | 21 | 16 |
Find the regression line of X on Y.
Find the line of best fit for the following data, treating x as the dependent variable (Regression equation x on y):
| X | 14 | 12 | 13 | 14 | 16 | 10 | 13 | 12 |
| Y | 14 | 23 | 17 | 24 | 18 | 25 | 23 | 24 |
Hence, estimate the value of x when y = 16.
A psychologist selected a random sample of 22 students. He grouped them in 11 pairs so that the students in each pair have nearly equal scores in an intelligence test. In each pair, one student was taught by method A and the other by method B and examined after the course. The marks obtained by them after the course are as follows:
| Pairs | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 |
| Methods A | 24 | 29 | 19 | 14 | 30 | 19 | 27 | 30 | 20 | 28 | 11 |
| Methods B | 37 | 35 | 16 | 26 | 23 | 27 | 19 | 20 | 16 | 11 | 21 |
Calculate Spearman’s Rank correlation.
Calculate Karl Pearson’s coefficient of correlation between x and y for the following data and interpret the result:
(1, 6), (2, 5), (3, 7), (4, 9), (5, 8), (6, 10), (7, 11), (8, 13), (9, 12)
If the regression line of x on y is, 9x + 3y − 46 = 0 and y on x is, 3x + 12y − 7 = 0, then the correlation coefficient ‘r’ is equal to:
For 5 observations of pairs (x, y) of variables X and Y, the following results are obtained:
∑x = 15, ∑y = 25, ∑x2 = 55, ∑y2 = 135, ∑xy = 83.
Calculate the value of bxy and byx.
If the two regression coefficients are 0.8 and 0.2, then the value of coefficient of correlation r will be ______.
The following table shows the Mean, the Standard Deviation and the coefficient of correlation of two variables x and y.
| Series | x | y |
| Mean | 8 | 6 |
| Standard deviation | 12 | 4 |
| Coefficient of correlation | 0.6 | |
Calculate:
- the regression coefficient bxy and byx
- the probable value of y when x = 20
Mean of x = 53, mean of y = 28 regression co-efficient y on x = −1.2, regression co-efficient x on y = −0.3. Find coefficient of correlation (r).
The random variables have regression lines 3x + 2y − 26 = 0 and 6x + y − 31 = 0. Calculate co-efficient of correlations.
